Can you?

Ok I have a question it`s a kind of a quest:
Can ypu overflow the buffer and call the function DontCallMe() in this sample code?

#include <stdio.h>

typedef char sbuf[10];

void getstring(sbuf is)
{
gets(is);
puts("You entered: ");
puts(is);
}

void DontCallMe()
{
puts ("Nice!");
}

void main ()
{
sbuf is = "Hi!";

puts("Enter something:");
getstring(is);
}

 

Что-то нифига я не понял, что ты хочешь....

 

Блин почитай про переполнение буфера.
Тут все просто...

 

0x080483f8 there`s the addres which you need to overrite the return...please english if it`s possible

 

to PxL
I'm sorry, but can you send me this compiled programm to mail [email protected] and I try to help you...

 

Hi, I gave the challange cause I tought you gues will like it. I know the answer

e.g. I`ll send the compiled code to you ..

 

Is there somebody else except me here who knows what realy is Buffer overflow?

 

I'm sorry, but I wait you too long time... =(((, so I can do it, but i don't have a executable program.. =((

 

Why you don`t just compile it?

 

Плохо по англиски говорю...

Вообщем
Chech the buffer size (overflow -range)) of varible.
Enter the adress of function DontCallMe...

Блин я статью пишу...